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-8t^2-15t+11=0
a = -8; b = -15; c = +11;
Δ = b2-4ac
Δ = -152-4·(-8)·11
Δ = 577
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{577}}{2*-8}=\frac{15-\sqrt{577}}{-16} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{577}}{2*-8}=\frac{15+\sqrt{577}}{-16} $
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